To achieve a speed of 3 m/s, the bottle must be dropped at m.

For an object dropped from rest, its speed after falling a distance h is given by v² = 2gh. Solving for distance gives h = v²/(2g) = 3²/(2 × 9.8) ≈ 0.46 m. Therefore, the bottle must be dropped from 0.46 m, choice A.

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