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3CuCl2 + 2Al 2AlCl3 + 3Cu Based on the balanced equation, the molar ratio of CuCl2 to Al should be .

Compare this ratio to the experimental number of moles computed above. The limiting reactant(s) is/are .
0.25 g Al equals moles
0.0093, .0093
3CuCl2 + 2Al 2AlCl3 + 3Cu Based on the balanced equation, the molar ratio of CuCl2 to Al should be 3:2. Compare this ratio to the experimental number of moles computed above. The limiting reactant(s) is/are .

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