You already saw that 1.00 g of Al should yield 3.53 g of copper for the reaction below.3CuCl2(aq) + 2Al(s)⟶ 2AlCl3(aq) + 3Cu(s)However, impurities and errors can occur easily. Suppose that only 2.86 g of copper is produced. What is the percent yield of the reaction?