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Special Linear Relationships - Question 1 | NHS Algebra Integrated Math II Semester 1 CR | Revolt

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Answers NHS Algebra Integrated Math II Semester 1 CR Special Linear RelationshipsQuestion 1

1

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Special Linear Relationships

Question 1 of 4 • NHS Algebra / Integrated Math II Semester 1 CR

The equation –3y = 15 – 4x rewritten in slope-intercept form is .

Answer

A

y = –(4/3)x – 5

B

y= –(4/3)x + 5

C

y = (4/3)x – 5

D

y= (4/3)x + 5

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Special Linear Relationships

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