Week 16 Test Answers

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Will surveyed students at his school about whether they have ever gone snowboarding and whether they own a skateboard. He found that 35 of the 99 students who own a skateboard have snowboarded. Also, there were 13 students who have snowboarded but do not own a skateboard, and 147 students who have never gone snowboarding and do not own a skateboard.

A
A 4-column table has 3 rows. The first column has entries skateboard, no skateboard, total. The second column is labeled have snowboarded with entries 35, 64, 99. The third column is labeled never snowboarded with entries 13, 147, 160. The fourth column is labeled Total with entries 48, 211, 256.
Option A
B
A 4-column table has 3 rows. The first column has entries skateboard, no skateboard, total. The second column is labeled have snowboarded with entries 35, 13, 48. The third column is labeled never snowboarded with entries 99, 147, 246. The fourth column is labeled Total with entries 134, 160, 294.
Option B
C
A 4-column table has 3 rows. The first column has entries skateboard, no skateboard, total. The second column is labeled have snowboarded with entries 35, 13, 48. The third column is labeled never snowboarded with entries 64, 147, 211. The fourth column is labeled Total with entries 99, 160, 259.
Option C
D
A 4-column table has 3 rows. The first column has entries skateboard, no skateboard, total. The second column is labeled have snowboarded with entries 35, 99, 134. The third column is labeled never snowboarded with entries 13, 147, 160. The fourth column is labeled Total with entries 48, 246, 294.
Option D
23

A 5-column table has 4 rows. The first column has entries A, B, C, Total. The second column is labeled X with entries 10, 110, 60, 180. The third column is labeled Y with entries 80, 44, 59, 183. The fourth column is labeled Z with entries 61, 126, 110, 297. The fifth column is labeled Total with entries 151, 280, 229, 660.

Question illustration
A
Z and B are independent events because P(Z∣B) = P(Z).
B
Z and B are independent events because P(Z∣B) = P(B).
C
Z and B are not independent events because P(Z∣B) ≠ P(Z).
D
Z and B are not independent events because P(Z∣B) ≠ P(B).

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Week 16 Test Answers — SLPS-1207350-Mathematics…