Trevor is pulling his younger brother in a wagon. He pulls the wagon 50 m to the corner with a force that is parallel with the ground. He then turns the wagon around and pulls it 50 m back to the starting point with the same force at an angle of 30° with respect to the ground.

Work is the force component in the direction of motion multiplied by the distance. On the first trip, the force is parallel to the ground, so all of it contributes: W = F × 50 m. On the return trip, only the component F cos 30° acts along the ground, so the work is F cos 30° × 50 m, which is less. Thus, he does less work coming back.

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