Which is the equation of a line that has a slope of negative 2 thirds and passes through point open paren negative 3 comma negative 1 close paren ?

Use slope-intercept form, y = mx + b, with slope m = -2/3. Substitute the point (-3, -1): -1 = (-2/3)(-3) + b = 2 + b, so b = -3. The equation is y = (-2/3)x - 3, which is choice B.

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