AnswersCR Math Analysis S1 M4050OXWriting Polynomial Functions from Complex Roots

Writing Polynomial Functions from Complex Roots Answers

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What are the zeroes of the function?

A
–3
B
–2
C
2
D
3
E
5
3

Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5. [image 1] Can any of the roots have multiplicity? [image 2] How can you find a function that has these roots?

Question illustration
Answer:

One such function is f(x) = (x − 2)(x − 3)(x − 5) = x³ − 10x² + 31x − 30. None of the roots can have multiplicity greater than 1 because the three distinct roots already account for the cubic’s degree. Write each root as a linear factor and multiply the factors.

4

Which of the following did you include in your explanation?

A
The roots cannot have multiplicity because the function is specified as cubic and 3 roots are given.
B
To find the function, write f(x) = (x – 2)(x – 3)(x – 5), and simplify the right side.
6

Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5).Describe the steps for writing the equation of this cubic polynomial function.

Answer:

Use the zeroes to determine the roots. Write the polynomial as a product of the leading coefficient, a, and the factors, where each factor is x minus a root. Use the y-intercept (0, –5) to solve for the leading coefficient. Substitute the leading coefficient into the polynomial function for a and simplify.

7

Which of the following did you include in your description?

A
Use the zeroes to determine the roots.
B
Write the polynomial as a product of the leading coefficient, a, and the factors, where each factor is x minus a root.
C
Use the y-intercept (0, –5) to solve for the leading coefficient.
D
Substitute the leading coefficient into the polynomial function for a and simplify.
9

The linear factors of the cubic are ✔ (x – 2)(x – 3)(x – 5)(x – 2)(x – 3)(x – 5)(x + 5)(x + 2)(x + 3)(x + 5)(x + 2)(x + 3)(x – 5).

A
✔ (x – 2)(x – 3)(x – 5)
B
(x – 2)(x – 3)(x – 5)(x + 5)
C
(x + 2)(x + 3)(x + 5)
D
(x + 2)(x + 3)(x – 5)
10

To solve for the leading coefficient, use a = –5(0 – 2)(0 – 3)(0 – 5) a = 5(0 – 2)(0 – 3)(0 – 5) 5 = a(0 – 2)(0 – 3)(0 – 5)✔ –5 = a(0 – 2)(0 – 3)(0 – 5).

A
a = –5(0 – 2)(0 – 3)(0 – 5)
B
a = 5(0 – 2)(0 – 3)(0 – 5)
C
5 = a(0 – 2)(0 – 3)(0 – 5)
D
✔ –5 = a(0 – 2)(0 – 3)(0 – 5)
14

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19

The equation of the polynomial function is:

A
f(x) = (x + (2 + i))(x + (2 – i))(x + 5)
B
f(x) = (x – (2 + i))(x – (2 – i))(x – 5)
C
f(x) = (x – (2 + i))(x – (2 – i))
D
f(x) = (x + (2 + i))(x – (2 – i))(x – 5)
20

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