Zero and Negative Exponents Answers
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1
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If , what is the value of x?
A
Negative 243
B
Negative StartFraction 1 Over 243 EndFraction
C
StartFraction 1 Over 243 EndFraction
D
2432
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Which is the simplified form of ?
A
StartFraction n Superscript 6 Over p cubed EndFraction
B
StartFraction 1 Over n Superscript 6 Baseline p cubed EndFraction
C
StartFraction p cubed Over n Superscript 6 EndFraction
D
n Superscript 6 Baseline p cubed
3
Tyler simplified the expression . His procedure is shown below.What is Tyler’s error?
A
Both powers should be in the numerator with positive exponents.B
Both powers should be in the denominator with positive exponents.C
The power should be in the numerator and the power in the denominator.
D
The power should be in the numerator and the power in the denominator.
4
What is the value of ?
A
Negative StartFraction 1 Over 196 EndFraction
B
StartFraction 1 Over 196 EndFraction
C
0D
15
Which is the simplified form of ?
A
x Superscript 12
B
Negative x Superscript 12
C
StartFraction 1 Over x Superscript 12 EndFraction
D
Negative StartFraction 1 Over x Superscript 12 EndFraction
7
The table shows a pattern of exponents.Powers of 5Value1252551What is the pattern as the exponents decrease?
A
subtract 5 from the previous valueB
subtract 100 from the previous valueC
divide the previous value by 5D
divide the previous value by 258
Which is the simplified form of ?
A
StartFraction 1 Over r Superscript 7 Baseline s Superscript 12 EndFraction
B
Negative r Superscript 7 Baseline minus s Superscript 12
C
StartFraction r Superscript 7 Over s Superscript 12 EndFraction
D
StartFraction 1 Over r Superscript 7 Baseline EndFraction + StartFraction 1 Over s Superscript 12 EndFraction
9
What is the pattern in the values as the exponents increase?Powers of 2Value1
A
add to the previous value
B
subtract from the previous value
C
divide the previous value by 2D
multiply the previous value by 210
What is the pattern in the values as the exponents increase?Powers of 3Value139
A
add 3 to the previous valueB
subtract 3 from the previous valueC
divide the previous value by 3D
multiply the previous value by 3Did you find these answers helpful?
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