Compositions Answers

The rule is applied to ΔABC.

Triangle A B C is reflected across the line of reflection m to form triangle A prime B prime C prime. Triangle A prime B prime C prime is rotated about point B prime 270 degrees to form triangle A double-prime B double-prime C double-prime.

Triangle JKL is transformed using the rule . Point K of the pre-image is at (4, 7).

Figure WXYZ is transformed using the rule . Point W of the pre-image is at (1, 6).

On a coordinate plane, 3 parallelograms are shown. Parallelogram A B C D has points (3, 5), (6, 5), (4, 1), (1, 1). Parallelogram A prime B prime C prime D prime has points (3, negative 5), (6, negative 5), (4, negative 1), (1, negative 1). Parallelogram A double-prime B double-prime C double-prime D double-prime has points (negative 3, negative 4), (0, negative 4), (negative 2, 0), (negative 4, 0).

Parallelogram F"G"H"J" is the final image after the rule was applied to parallelogram FGHJ.

Trapezoid E F G H is reflected across line of reflection k to form trapezoid E prime F prime G prime H prime. Trapezoid E prime F prime G prime H prime is shifted down to E double-prime F double-prime G double-prime H double-prime.

Trapezoid G H J K is rotated about G 90 degrees counterclockwise to form trapezoid G prime H prime J prime K prime. Trapezoid G prime H prime J prime K prime is reflected across the line of reflection m to form trapezoid G double-prime H double-prime J double-prime K double-prime.

Question text not available

Which ordered pairs name the coordinates of vertices of the pre-image, trapezoid ABCD? Select two options.