Reflections Answers

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The image of ΔABC after a reflection across is ΔA'B'C'.

Question illustration
A
F is the midpoint of AA' because bisects AA'.
Option A
B
F is the midpoint of EG because AA' bisects EG.
C
F is the midpoint of AA' because AA' bisects EG.
D
F is the midpoint of EG because bisects AA'.
Option D
2
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A point has the coordinates (0, k).Which reflection of the point will produce an image at the same coordinates, (0, k)?

a
a reflection of the point across the x-axis
a
a reflection of the point across the y-axis
a
a reflection of the point across the line y = x
a
a reflection of the point across the line y = –x
5

A line segment has endpoints at (–4, –6) and (–6, 4). Which reflection will produce an image with endpoints at (4, –6) and (6, 4)?

A
a reflection of the line segment across the x-axis
B
a reflection of the line segment across the y-axis
C
a reflection of the line segment across the line y = x
D
a reflection of the line segment across the line y = –x
8

Which statements must be true about the reflection of ΔXYZ across ? Select three options.

Question illustration
A
m∠X'Z'Y' = 90°
B
m∠MCY = 90°
C
XX' ≅ YY'
D
BZ' ≅ BZ
E
XY || X'Y'
10

For to be the line of reflection between and , which statements must be true? Select three options.

Question illustration
A
BD = DB'
B
DF = FG
C
m∠EFA = 90°
D
The line of reflection, EH, is the perpendicular bisector of BB', AA', and CC'.
E
ΔABC is not congruent to ΔA'B'C'.

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