On a coordinate plane, 2 triangles are shown. Triangle 1 has points at A (negative 3, 4), B (negative 2, 1), C (negative 4, 1). Triangle 2 has points at A prime (4, negative 2), B prime (3, negative 5), C prime (5, negative 5).

The proof that ΔABC ≅ ΔCDA is shown.Given: ∥ and ∥ Prove: ΔABC ≅ ΔCDA

Triangle ABC has the angle measures shown.





What additional information could be used to prove ΔABC ≅ ΔMQR using SAS? Select two options.
On a coordinate plane, a triangle has points A prime (negative 2, 10), B prime (negative 6, 4), and (negative 10, 8).

Triangles K L P and Q M N are shown. Triangle Q M N is slightly higher than triangle K L P and side Q M connects to side K P. Point M is at the midpoint of K P. Sides K L and Q N are congruent. Angles K L P and Q N M are congruent. Angles K P L and Q M N are both right angles.





The triangles are congruent by the SSS congruence theorem.

Point O is the incenter of ΔABC.

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