AnswersAlgebra 2-1st Semester-CR KCKPS 02101040Unit Test — Cumulative examQuestion 9
9
RCMultiple Choice

Unit Test — Cumulative exam

Question 9 • Algebra 2-1st Semester-CR (KCKPS 02101040)

What are the solutions of the equation (x + 2)2 – 2(x + 2) – 15 = 0? Use u substitution to solve.

Answer
A
x = –7 and x = 1
B
x = –5 and x = 3
C
x = –3 and x = 5
D
x = –1 and x = 7
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