AnswersGeometry - Semester 1 PathwaysUsing Triangle Congruence Theorems

Using Triangle Congruence Theorems — Cumulative exam Answers

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4

Which function has the same maximum value as f(x) = – |x + 3| – 2?

A
Option
Option A
B
f(x) = (x + 3)2 – 2
C
Option
Option C
D
f(x) = –(x – 6)2 – 3
5

Angles 1 and 2 are supplementary.

Question illustration
A
m1 + m2 = 90°
Option A
B
m1 + m2 = 100°
Option B
C
m1 + m2 = 180°
Option C
D
m1 + m2 = 200°
Option D
7

The step function g(x) is defined as shown.g(x) = What is the range of g(x)?

Question illustration
A
–3 ≤ g(x) ≤ 5
B
0 ≤ g(x) ≤ 10
C
{–3, 2, 5}
D
{0, 4, 10}
8

Which equation represents a graph with a vertex at (1, –6)?

A
y = 3x2 + 6x – 3
B
y = 3x2 – 6x – 3
C
y = 3x2 – 8x – 1
D
y = 3x2 – 3x – 6
11

Omar grouped the terms and factored the GCF out of the groups of the polynomial 3x3 – 15x2 – 4x + 20. His work is shown.Step 1: (3x3 – 15x2) + (–4x + 20)Step 2: 3x2(x – 5) + 4(–x + 5)

A
Omar should realize that his work shows that the polynomial is prime.
B
Omar should go back and regroup the terms in Step 1 as (3x3 – 15x2) – (4x + 20).
C
In Step 2, Omar should factor only out of the first expression.
D
Omar should factor out a negative from one of the groups so the binomials will be the same.
13

Marisol grouped the terms and factored the GCF out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. Her work is shown.Step 1: (6x3 – 22x2) – (9x + 33)Step 2: 2x2(3x – 11) – 3(3x + 11)

A
Marisol should realize that her work shows that the polynomial is prime.
B
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).
C
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) + (9x – 33).
D
Marisol should refactor the expression in Step 2 as 2x2(3x + 11) – 3(3x + 11).
14

When graphed, which parabola opens downward?

Question illustration
y
y = –3x2
y
y = (x – 3)2
C
Option
Option C
y
y = x2 – 3
15

What is a solution to (x + 6)(x + 2) = 60?

A
x = −6
B
x = −4
C
x = 4
D
x = 12
16

Which equation is an example of the commutative property of multiplication?

A
(4 + 2i) = (2i + 4)
B
(4 + 2i)(3 – 5i) = (3 – 5i)(4 + 2i)
C
(4 + 2i)(3 – 5i) = (4 + 2i)(3 – 5i)(1)
D
(4 + 2i) = (4 + 2i + 0)
17

Solve for in the equation .

Question illustration
A
x = negative 11 plus-or-minus StartFraction 25 Over 2 EndFraction
Option A
B
x = negative eleven-halves plus-or-minus StartFraction 25 Over 2 EndFraction
Option B
C
x = negative 11 plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Option C
D
x = negative eleven-halves plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Option D
18

Which is true about the completely simplified difference of the polynomials 6x6 − x3y4 − 5xy5 and 4x5y + 2x3y4 + 5xy5?

A
The difference has 3 terms and a degree of 6.
B
The difference has 4 terms and a degree of 6.
C
The difference has 3 terms and a degree of 7.
D
The difference has 4 terms and a degree of 7.
19

Question text not available

Question illustration
B
Both the domain and range of the transformed function are the same as those of the parent function.
N
Neither the domain nor the range of the transformed function are the same as those of the parent function.
T
The range of the transformed function is the same as the parent function, but the domains of the functions are different.
T
The domain of the transformed function is the same as the parent function, but the ranges of the functions are different.

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