Unit Test — Cumulative exam Answers

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3

What are the domain and range of ?

Question illustration
d
domain: x > 1; range: y > 2
d
domain: x > 1; range: all real numbers
d
domain: all real numbers; range: y > 1
d
domain: all real numbers; range: all real numbers
4

Which equation has x = 4 as the solution?

A
log Subscript 4 Baseline (3 x + 4) = 2
Option A
B
log Subscript 3 Baseline (2 x minus 5) = 2
Option B
C
log Subscript x Baseline 64 = 4
Option C
D
log Subscript x Baseline 16 = 4
Option D
8

What is the area of triangle ABC? Round to the nearest square unit.

Question illustration
A
8 square units
B
15 square units
C
33 square units
D
618 square units
9

For what values of x does ?

Question illustration
A
x = –3, x = 1
B
x = –1, x = 3
C
x = negative three-halves, x = 2
Option C
D
x = negative 2, x = three-halves
Option D
10

A simple random sample of size n is drawn from a normally distributed population, and the mean of the sample is , while the standard deviation is s. What is the 90% confidence interval for the population mean? Use the table below to help you answer the question.Confidence Level90%95%99%z*-score1.6451.962.58

Question illustration
A
x Overbar plus-or-minus StartFraction 0.90 times s Over StartRoot n EndRoot EndFraction
Option A
B
x Overbar plus-or-minus StartFraction 1.645 times s Over StartRoot n EndRoot EndFraction
Option B
C
x Overbar plus-or-minus StartFraction 1.96 times s Over StartRoot n EndRoot EndFraction
Option C
D
x Overbar plus-or-minus StartFraction 2.58 times s Over StartRoot n EndRoot EndFraction
Option D
11

What are the exact values of the six trigonometric functions for radians?

Question illustration
A
sine (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction StartRoot 3 EndRoot Over 2 EndFraction; cosine (Negative StartFraction 7 pi Over 6 EndFraction) = Negative one-half; tangent (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartRoot 3 EndRoot. Cosecant (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction 2 StartRoot 3 EndRoot Over 3 EndFraction; secant (Negative StartFraction 7 pi Over 6 EndFraction) = 2; Cotangent (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction StartRoot 3 EndRoot Over 3 EndFraction
Option A
B
sine (Negative StartFraction 7 pi Over 6 EndFraction) = Negative one-half; cosine (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction StartRoot 3 EndRoot Over 2 EndFraction; tangent (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction StartRoot 3 EndRoot Over 3 EndFraction. Cosecant (Negative StartFraction 7 pi Over 6 EndFraction) = Negative 2; secant (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction 2 StartRoot 3 EndRoot Over 3 EndFraction; Cotangent (Negative StartFraction 7 pi Over 6 EndFraction) = StartRoot 3 EndRoot
Option B
C
sine (Negative StartFraction 7 pi Over 6 EndFraction) = one-half; cosine (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction StartRoot 3 EndRoot Over 2 EndFraction; tangent (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction StartRoot 3 EndRoot Over 3 EndFraction. Cosecant (Negative StartFraction 7 pi Over 6 EndFraction) = 2; secant (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction 2 StartRoot 3 EndRoot Over 3 EndFraction; Cotangent (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartRoot 3 EndRoot
Option C
D
sine (Negative StartFraction 7 pi Over 6 EndFraction) = StartFraction StartRoot 3 EndRoot Over 3 EndFraction; cosine (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction StartRoot 3 EndRoot Over 2 EndFraction; tangent (Negative StartFraction 7 pi Over 6 EndFraction) = StartRoot 3 EndRoot. Cosecant (Negative StartFraction 7 pi Over 6 EndFraction) = StartRoot 3 EndRoot; secant (Negative StartFraction 7 pi Over 6 EndFraction) = Negative StartFraction 2 StartRoot 3 EndRoot Over 3 EndFraction; Cotangent (Negative StartFraction 7 pi Over 6 EndFraction) = StartFraction StartRoot 3 EndRoot Over 3 EndFraction
Option D
13

What are the solutions to

Question illustration
A
x = negative 2 and x = negative 4
Option A
B
x = negative 1 and x = 8
Option B
C
x = 1 and x = negative 8
Option C
D
x = 2 and x = 4
Option D
16

Identify the equation that translates five units down.

Question illustration
A
y = l n (x minus 5)
Option A
B
y = l n (x) + 5
Option B
C
y = l n (x + 5)
Option C
D
y = l n (x) minus 5
Option D
17

What is rewritten using the power property?

Question illustration
A
e log Subscript 6 Baseline f
Option A
B
f log Subscript 6 Baseline e
Option B
C
log Subscript 6 Baseline (e times f)
Option C
D
log Subscript 6 Baseline (e + f)
Option D
18

The depth of the water at the end of a pier changes periodically along with the movement of tides. On a particular day, low tides occur at 12:00 a.m. and 3:30 p.m., with a depth of 3.25 meters, while high tides occur at 7:45 a.m. and 11:15 p.m., with a depth of 8.75 meters. Which of the following equations models d, the depth of the water in meters, as a function of time, t, in hours? Let t = 0 be 12:00 a.m.

A
d = negative 3.75 cosine (StartFraction 4 pi Over 31 EndFraction t) + 5
Option A
B
d = negative 3.75 cosine (StartFraction 4 pi Over 29 EndFraction t) + 5
Option B
C
d = negative 2.75 cosine (StartFraction 4 pi Over 31 EndFraction t) + 6
Option C
D
d = negative 2.75 cosine (StartFraction 4 pi Over 29 EndFraction t) + 6
Option D

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