Answers FL-1200330-Algebra 2 Sem 1 - FlexLiteral Equations

Literal Equations Answers

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Gavin wrote the equation to represent p, the profit he makes from s sales in his lawn-mowing business. Which equation is solved for s?

s = StartFraction p minus 100 Over 3 EndFraction

s = StartFraction 4 p minus 300 Over 3 EndFraction

s = StartFraction 4 p Over 300 EndFraction

s = StartFraction 400 p Over 3 EndFraction

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Remmi wrote the equation of the line He solved for x and got Which of the following is an equivalent equation for x?

x = y minus eleven-thirds

x = y + seven-thirds

x = 3 (y minus two-thirds)

x = 3 (y + two-thirds)

The equation is the slope-intercept form of the equation of a line. What is the equation solved for b?

y minus m = b

y minus m x = b

StartFraction y Over m x EndFraction = b

StartFraction y Over m EndFraction minus x = b

The area of a sector of a circle is given by the equation , where r is the radius of the circle and S is the angle measure of the sector. If Mia solved this equation for S, which of the following equations did she write?

360 uppercase A + pi r squared

360 uppercase A minus pi r squared

StartFraction 360 + uppercase A Over pi r squared EndFraction

StartFraction 360 uppercase A Over pi r squared EndFraction

The final velocity, V, of an object under constant acceleration can be found using the formula , where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?

uppercase V squared minus v squared minus 2 x = a

uppercase V squared minus v squared + 2 s = a

StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a

StartFraction uppercase V squared plus v squared Over 2 s EndFraction = a

Which equation is equivalent to

s = t minus 2

s = StartFraction 4 Over t + 2 EndFraction

s = StartFraction t + 2 Over 4 EndFraction

s = t + 6

The formula gives the partial sum of an arithmetic sequence. What is the formula solved for an?

a Subscript n Baseline = StartFraction 2 uppercase S minus a Subscript 1 Baseline n Over n EndFraction

a Subscript n Baseline = StartFraction 2 uppercase S + a Subscript 1 Baseline n Over n EndFraction

a Subscript n Baseline = 2 uppercase S + a Subscript 1 Baseline n + n

a Subscript n Baseline = 2 uppercase S minus a Subscript 1 Baseline n + n

A student solves the equation for v. Start with the original equation.Use the division property of equality.Use the multiplication property of equality.Use the square root property of equality.Simplify.Which statement explains how to correct the error that was made?