A stock solution is made by dissolving 66 point 0 5 g of open paren NH sub 4 close paren sub 2 SO sub 4 in enough water to make 250 milliliters of solution. cap A 10 point 0 mL sample of this solution is then diluted to 50 point 0 milliliters Given that the molar mass of open paren NH sub 4 close paren sub 2 SO sub 4 is 132 point 1 g/mol , what is the concentration of the new solution? Use cap m sub i cap v sub i is equal to cap m sub f cap v sub f and molarity is equal to moles of solute over liters of solution