Question 9 • Algebra II
Rewrite the first radical as ∛(54A) = ∛(27·2A) = 3∛(2A), so its term becomes 9b²∛(2A). In the second term, ∛(2Ab⁶) = b²∛(2A), making that term 3b²∛(2A). Adding like radicals gives 12b²∛(2A), which is choice A.
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