AnswersCR - Algebra 2 26-27 - S1Quadratic in Form Polynomials

Quadratic in Form Polynomials Answers

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3

What are the solutions of the quadratic equation (x – 8)2 – 13(x – 8) + 30 = 0? Use u substitution to solve.

A
x = –11 and x = –18
B
x = –2 and x = 5
C
x = 2 and x = –5
D
x = 11 and x = 18
4

Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0?

A
u2 – 11u + 24 = 0 where u = (x2 – 1)
B
(u2)2 – 11(u2) + 24 where u = (x2 – 1)
C
u2 + 1 – 11u + 24 = 0 where u = (x2 – 1)
D
(u2 – 1)2 – 11(u2 – 1) + 24 where u = (x2 – 1)
5

Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) – 6 = 0?

A
(u + 2)2 + 5(u + 2) – 6 = 0 where u = (x – 2)
B
u2 + 4 + 5u – 6 = 0 where u = (x – 2)
C
u2 + 5u – 6 = 0 where u = (x + 2)
D
u2 + u – 6 = 0 where u = (x + 2)
6

Which equation is quadratic in form?

A
2(x + 5)3 + 8x + 5 + 6 = 0
B
x6 + 6x4 + 8 = 0
C
7x6 + 36x3 + 5 = 0
D
4x9 + 20x3 + 25 = 0
9

What is the solution of the equation (x – 5)2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.

A
x = StartFraction negative 3 plus-or-minus 3 i StartRoot 3 EndRoot Over 2 EndFraction
Option A
B
x = StartFraction 7 plus-or-minus 3 i StartRoot 3 EndRoot Over 2 EndFraction
Option B
C
x = 2
D
x = 8

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Quadratic in Form Polynomials Answers — CR …