AnswersAlgebra 2 - Semester 1 PathwaysQuadratic in Form Polynomials

Quadratic in Form Polynomials Answers

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Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) – 6 = 0?

A
(u + 2)2 + 5(u + 2) – 6 = 0 where u = (x – 2)
B
u2 + 4 + 5u – 6 = 0 where u = (x – 2)
C
u2 + 5u – 6 = 0 where u = (x + 2)
D
u2 + u – 6 = 0 where u = (x + 2)
3

Which quadratic equation is equivalent to (x – 4)2 – (x – 4) – 6 = 0?

A
(u – 4)2 – (u – 4) – 6 = 0 where u = (x – 4)
B
u2 – (u – 4) – 6 = 0 where u = (x – 4)
C
u2 – 16 – u – 6 = 0 where u = (x – 4)
D
u2 – u – 6 = 0 where u = (x – 4)
7

What is the solution of the equation (x – 5)2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.

A
x = StartFraction negative 3 plus-or-minus 3 i StartRoot 3 EndRoot Over 2 EndFraction
Option A
B
x = StartFraction 7 plus-or-minus 3 i StartRoot 3 EndRoot Over 2 EndFraction
Option B
C
x = 2
D
x = 8
8

Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0?

A
u2 – 11u + 24 = 0 where u = (x2 – 1)
B
(u2)2 – 11(u2) + 24 where u = (x2 – 1)
C
u2 + 1 – 11u + 24 = 0 where u = (x2 – 1)
D
(u2 – 1)2 – 11(u2 – 1) + 24 where u = (x2 – 1)
11

What substitution should be used to rewrite 4x4 – 21x2 + 20 = 0 as a quadratic equation?

A
u = x2
B
u = 2x2
C
u = x4
D
u = 4x4
12

What are the solutions of the equation x4 – 9x2 + 8 = 0? Use u substitution to solve.

A
x = 1 and x =
Option A
B
x = ±1 and
Option B
C
x = ±i and
Option C
D
x = ±i and
Option D
13

Which equation is quadratic in form?

A
4(x – 2)2 + 3x – 2 + 1 = 0
B
8x5 + 4x3 + 1 = 0
C
10x8 + 7x4 + 1 = 0
D
9x16 + 6x4 + 1 = 0
14

What substitution should be used to rewrite 16(x3 + 1)2 – 22(x3 + 1) – 3 = 0 as a quadratic equation?

A
u = (x3)
B
u = (x3 + 1)
C
u = (x3 + 1)2
D
u = (x3 + 1)3
15

What are the solutions of the quadratic equation (x – 8)2 – 13(x – 8) + 30 = 0? Use u substitution to solve.

A
x = –11 and x = –18
B
x = –2 and x = 5
C
x = 2 and x = –5
D
x = 11 and x = 18

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