Use substitution to write an equivalent quadratic equation.(3x + 2)2 + 7(3x + 2) – 8 = 0u² + 7u - 8 = 0, where u = (3x + 2)²u² + 7u - 8 = 0, where u = 3x + 2u² + 7u - 8 = 0, where u = 7(3x + 2)u² + u - 8 = 0
A
u² + 7u - 8 = 0, where u = (3x + 2)²B
u² + 7u - 8 = 0, where u = 3x + 2C
u² + 7u - 8 = 0, where u = 7(3x + 2)