Use substitution to write an equivalent quadratic equation.(3x + 2)2 + 7(3x + 2) – 8 = 0u² + 7u - 8 = 0, where u = (3x + 2)²✔ u² + 7u - 8 = 0, where u = 3x + 2u² + 7u - 8 = 0, where u = 7(3x + 2)u² + u - 8 = 0
Select all of the zeroes of the function.




Which equation is equivalent tof(x) = 16x4 – 81 = 0?(4x² - 9)(4x² - 9) = 0✔ (4x² + 9)(4x² - 9) = 0(4x - 9)(4x - 9) = 0(4x + 9)(4x - 9) = 0
Solve (x + 3)2 + (x + 3) – 2 = 0.Let u = x✔ x + 3(x + 3)²x²
Rewrite the equation in terms of u.
What are the solutions of the original equation?x = 1 or x = –2x = –1 or x = 2✔ x = –5 or x = –2x = 4 or x = –5
Solve the equation 6(2x + 4)2 = (2x + 4) + 2.




Solve (x + 4)2 – 3(x + 4) – 3 = 0 using substitution.u = x✔ x + 43(x + 4)(x + 4)²
Factor the equation. ✔ (u + 2)(u – 1) = 0(u + 1)(u – 2) = 0(u – 2)(u – 1) = 0
Select the solution(s) of the original equation.




Examine the criteria below. Check which of these you included in your response.

Solve x4 – 17x2 + 16 = 0.Let u = x17x²✔ x²-17x².
Rewrite the equation in terms of u. u² - 17u - 16 = 017u² + u + 16 = 0-u² + 17u + 16 = 0✔ u² - 17u + 16 = 0
Factor. (u + 16)(u + 1) = 0✔ (u - 16)(u - 1) = 0(u + 17)(u - 1) = 0
Select all of the solutions to the original equation.
What are the solutions of 4x4 – 4x2 = 8?


Is the equation x9 – 5x3 + 6 = 0 quadratic in form? Explain why or why not.
No. It is not quadratic in form because (x³)² = x⁶, not x⁹, so the variable part of the first term is not the square of the variable part of the second term.
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