AnswersCR - Algebra 2 26-27 - S2Solving Logarithmic Equations using Technology

Solving Logarithmic Equations using Technology Answers

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Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a 1 and b 1?

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Tyler applied the change of base formula to a logarithmic expression. The resulting expression is shown below. Which expression could be Tyler’s original expression?

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Devonte used the change of base formula to approximate . Which expression did Devonte use?

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Log StartFraction 8 Over 25 EndFraction
Option A
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StartFraction log 8 Over log 25 EndFraction
Option B
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log StartFraction 25 Over 8 EndFraction
Option C
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StartFraction log 25 Over log 8 EndFraction
Option D
4

A student solved the equation below by graphing.Which statement about the graph is true?

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The curves do not intersect.
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The curves intersect at one point.
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The curves intersect at two points.
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The curves appear to coincide.
5

What is the approximate value of x in the equation below.

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–3.396
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–0.708
0
0.304
0
0.955
6

Which expression results when the change of base formula is applied to ?

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7

What is the approximate value of q in the equation below?

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–1.613
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–1.522
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0.585
3
3.079
8

Consider the equation below.Which system of equations can represent the equation?

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9

Which system of equations could be graphed to solve the equation below?

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y 1 = 3 x, y 2 = 2 x
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y 1 = log (2 x + 1), y 2 = 3 x minus 2
Option B
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y 1 = log 2 x + 1, y 2 = 3 x minus 2
Option C
D
y 1 = log (2 x + 1 + 2), y 2 = 3 x
Option D
10

Which system of equations could be graphed to solve the equation below?

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A
y 1 = StartFraction log 0.5 Over x EndFraction , y 2 = StartFraction log 3 Over 2 + x EndFraction
Option A
B
y 1 = StartFraction log x Over log 0.5 EndFraction, y 2 = StartFraction log 2 + x Over log 3 EndFraction
Option B
C
y 1 = StartFraction log 0.5 Over log 3 EndFraction, y 2 = StartFraction log x Over log 2 + x EndFraction
Option C
D
y 1 = StartFraction log x Over log 0.5 EndFraction, y 2 = StartFraction log 2 Over log 3 EndFraction + x
Option D

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