AnswersFL-1200330-Algebra 2 Sem 1 - FlexSolving Quadratic Equations by Factoring

Solving Quadratic Equations by Factoring Answers

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A rectangular deck is 12 ft by 14 ft. When the length and width are increased by the same amount, the area becomes 288 sq. ft. By how much were the dimensions increased?

A
2 ft
B
4 ft
C
8 ft
D
10 ft
2
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What are the solutions to the equation (x – 6)(x + 8) = 0?

A
x = –6 or x = 8
B
x = –6 or x = –8
C
x = 6 or x = –8
D
x = 6 or x = 8
3

A rectangular field has an area of 1,764 m2. The width of the field is 13 m more than the length. What is the perimeter of the field?

A
121 m
B
144 m
C
168 m
D
170 m
4

The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t – 16t2. How long after launch does the projectile return to the ground?

A
2 seconds
B
4 seconds
C
14 seconds
D
16 seconds
5

The profit a company makes from producing x tabletops is modeled by the equation P(x) = 480x – 2x2. For what number of tabletops does the company make a profit of $0?

A
100 tabletops
B
120 tabletops
C
240 tabletops
D
480 tabletops
6

Use the zero product property to find the solutions to the equation (x + 2) (x + 3) = 12.

A
x = –6 or x = 1
B
x = –3 or x = –2
C
x = –1 or x = 6
D
x = 2 or x = 3
7

The square of a number is 12 less than 7 times the number. What is the number?

A
–4 or –3
B
–4 or 3
C
–3 or 4
D
3 or 4
8

Use the zero product property to find the solutions to the equation x2 – 13x + 30 = 0.

A
x = –10 or x = –3
B
x = –10 or x = 3
C
x = –3 or x = 10
D
x = 3 or x = 10
9

The hypotenuse of a right triangle is 52 in. One leg of the triangle is 8 in. more than twice the length of the other. What is the perimeter of the triangle?

A
20 in.
B
26 in.
C
120 in.
D
138 in.
10

The solutions to the equation are or

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