AnswersCommon Core Math III ACompleting The Square

Solving Quadratic Equations: Completing the Square (Continued) Answers

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Gio is solving the quadratic equation by completing the square.5x2 + 15x – 4 = 0

A
Isolate the constant.
B
Factor 5 out of the variable terms.
C
Isolate the variable x.
D
Add 9 to both sides of the equation.
2
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Tran is solving the quadratic equation 2x2 – 4x – 3 = 0 by completing the square. His first four steps are shown in the table.

Question illustration
A
Step 1
B
Step 2
C
Step 3
D
Step 4
3

Lie is solving the quadratic equation by completing the square.3x2 + 18x – 8 = 0 3x2 + 18x = 8

A
Write the polynomial as a binomial squared.
B
Factor 3 out of the variable terms.
C
Isolate the variable x.
D
Add 8 to both sides of the equation.
4

The first few steps in solving the quadratic equation 8x2 + 80x = −5 by completing the square are shown.8x2 + 80x = −58(x2 + 10x) = −58(x2 + 10x + 25) = −5 + ______

A
−200
B
−25
C
25
D
200
5

Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Select three options.

Question illustration
A
8(x2 + 2x + 1) = –3 + 8
B
x = –1
Option B
C
x = –1
Option C
D
8(x2 + 2x + 1) = 3 + 1
E
8(x2 + 2x) = –3
6

Yvonne is solving the quadratic equation 6x2 + 24x + 7 = 0 by completing the square. Her first four steps are shown in the table.

Question illustration
A
Step 1
B
Step 2
C
Step 3
D
Step 4
7

What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15?

A
x = –1 – and x = –1 +
Option A
B
x = –1 – and x = –1 +
Option B
C
x = 1 – and x = 1 +
Option C
D
x = 1 – and x = 1 +
Option D
8

What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7?

A
x = –1 – and x = –1 +
Option A
B
x = –1 – and x = –1 +
Option B
C
x = –1 – and x = –1 +
Option C
D
x = –1 – and x = –1 +
Option D
9

Atraeus is solving the quadratic equation by completing the square.7x2 – 14x + 6 = 0 7x2 – 14x = –6 A(x2 – 2x) = –6

A
–14
B
2
C
6
D
7
10

Which is a zero of the quadratic function f(x) = 16x2 + 32x − 9?

A
x = –5.25
B
x = –2.25
C
x = –1.25
D
x = –0.25

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