Square Root Functions Answers
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1
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Which equation can be simplified to find the inverse of y = 2x2?
A
StartFraction 1 Over y EndFraction = 2 x squared
B
y = one-half x squared
C
–y = 2x2D
x = 2y22
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If , which inequality can be used to find the domain of f(x)?
A
StartRoot x minus 3 EndRoot greater-than-or-equal-to 0
B
x minus 3 greater-than-or-equal-to 0
C
StartRoot x minus 3 EndRoot less-than-or-equal-to 0
D
x minus 3 less-than-or-equal-to 0
3
Which equation is the inverse of y = 100 – x2?
A
y = plus-or-minus StartRoot 100 minus x EndRoot
B
y = 10 plus-or-minus StartRoot x EndRoot
C
y = 100 plus-or-minus StartRoot x EndRoot
D
y = plus-or-minus StartRoot x minus 100 EndRoot
4
Which could be the function graphed below?
A
f (x) = StartRoot x EndRoot minus 2
B
f (x) = StartRoot x minus 3 EndRoot + 1
C
f (x) = StartRoot 2x + 4 EndRoot
D
f (x) = StartRoot x + 1 EndRoot + 8
5
What is the domain of the function ?
A
x greater-than-or-equal-to negative 7
B
x greater-than-or-equal-to negative 6
C
x greater-than-or-equal-to 6
D
x greater-than-or-equal-to 7
6
Which equation is the inverse of y = 2x2 – 8?
A
y = plus-or-minus StartRoot StartFraction x + 8 Over 2 EndFraction EndRoot
B
y = StartFraction plus-or-minus StartRoot x + 8 EndRoot Over 2 EndFraction
C
y = plus-or-minus StartRoot StartFraction x Over 2 EndFraction + 8 EndRoot
D
y = StartFraction plus-or-minus StartRoot x EndRoot Over 2 EndFraction + 4
7
If , which inequality can be used to find the domain of f(x)?
A
StartRoot one-half x EndRoot greater-than-or-equal-to 0
B
One-half x greater-than-or-equal-to 0
C
One-half x minus 10 greater-than-or-equal-to 0
D
StartRoot one-half x minus 10 EndRoot + 3 greater-than-or-equal-to 0
8
What is the domain of the function ?
A
Negative infinity less-than x less-than infinity
B
Negative 4 less-than-or-equal-to x less-than infinity
C
0 less-than-or-equal-to x less-than infinity
D
4 less-than-or-equal-to x less-than infinity
9
Which equation is the inverse of y = 16x2 + 1?
A
y = plus-or-minus StartRoot StartFraction x Over 16 EndFraction minus 1 EndRoot
B
y = StartFraction plus-or-minus StartRoot x minus 1 EndRoot Over 16 EndFraction
C
y = StartFraction plus-or-minus StartRoot x EndRoot Over 4 EndFraction minus one-fourth
D
y = StartFraction plus-or-minus StartRoot x minus 1 EndRoot Over 4 EndFraction
10
Which equation can be simplified to find the inverse of y = 5x2 + 10?
A
x = 5y2 + 10B
StartFraction 1 Over y EndFraction = 5 x squared + 10
C
–y = 5x2 + 10D
y = one-fifth x squared + one-tenth
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