Square Root Functions Answers
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1
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Which equation is the inverse of y = 16x2 + 1?
A
y = plus-or-minus StartRoot StartFraction x Over 16 EndFraction minus 1 EndRoot
B
y = StartFraction plus-or-minus StartRoot x minus 1 EndRoot Over 16 EndFraction
C
y = StartFraction plus-or-minus StartRoot x EndRoot Over 4 EndFraction minus one-fourth
D
y = StartFraction plus-or-minus StartRoot x minus 1 EndRoot Over 4 EndFraction
2
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Which equation is the inverse of 2(x – 2)2 = 8(7 + y)?
A
–2(x – 2)2 = –8(7 + y)B
y = one-fourth x squared minus x minus 6
C
y = negative 2 plus-or-minus StartRoot 28 + 4 x EndRoot
D
y = 2 plus-or-minus StartRoot 28 + 4 x EndRoot
3
Which equation can be simplified to find the inverse of y = 5x2 + 10?
A
x = 5y2 + 10B
StartFraction 1 Over y EndFraction = 5 x squared + 10
C
–y = 5x2 + 10D
y = one-fifth x squared + one-tenth
4
What is the domain of the function ?
A
x greater-than-or-equal-to negative 7
B
x greater-than-or-equal-to negative 6
C
x greater-than-or-equal-to 6
D
x greater-than-or-equal-to 7
5
Which equation can be simplified to find the inverse of y = x2 – 7?
A
x = y squared minus one-seventh
B
StartFraction 1 Over x EndFraction = y squared minus 7
C
x = y2 – 7D
–x = y2 – 76
Which equation can be simplified to find the inverse of y = 2x2?
A
StartFraction 1 Over y EndFraction = 2 x squared
B
y = one-half x squared
C
–y = 2x2D
x = 2y27
What is the domain of the square root function graphed below?
A
x greater-than 1
B
x greater-than-or-equal-to 10
C
x greater-than 3
D
x greater-than-or-equal-to 3
8
What is the domain of the function ?
A
Negative infinity less-than x less-than infinity
B
Negative 4 less-than-or-equal-to x less-than infinity
C
0 less-than-or-equal-to x less-than infinity
D
4 less-than-or-equal-to x less-than infinity
9
Which could be the function graphed below?
A
f (x) = StartRoot x EndRoot minus 2
B
f (x) = StartRoot x minus 3 EndRoot + 1
C
f (x) = StartRoot 2x + 4 EndRoot
D
f (x) = StartRoot x + 1 EndRoot + 8
10
Which equation is the inverse of y = 100 – x2?
A
y = plus-or-minus StartRoot 100 minus x EndRoot
B
y = 10 plus-or-minus StartRoot x EndRoot
C
y = 100 plus-or-minus StartRoot x EndRoot
D
y = plus-or-minus StartRoot x minus 100 EndRoot
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