Solving One-Variable Inequalities — Unit test Answers

11 verified answers5 views
1
Free Preview

Ahmed simplified the expression to .Which procedure can Ahmed follow to verify that he did the simplification process correctly?

Question illustration
A
Substitute 2 into each expression, and evaluate them.
B
Add to .
Option B
C
Substitute 1 into the first expression, substitute 2 into the second expression, and evaluate them.
D
Subtract from .
Option D
2
Free Preview

Which expression is equivalent to ?

Question illustration
A
6 x squared minus y + 6 x squared minus 5 y
Option A
B
6 x squared minus y + 3 x squared minus 4 y
Option B
C
10 x squared minus 4 y + 2 x squared minus y
Option C
D
11 x squared + 2 y + x squared minus 3 y
Option D
3

Genevieve wants to verify that is the simplified expression of .Which procedure can Genevieve follow to verify this?

Question illustration
A
Add and .
Option A
B
Put an equal sign between and and then solve for x.
Option B
C
Substitute 5 for the first x, substitute 4 for the second x, then evaluate.
D
Substitute 5 into the expression and evaluate.
5

Veronique tried four different solutions to the matching problem shown. Which of her four answers would be the correct one?TermDefinitionvariablea numerical factor of a term that has a variablecoefficienta letter or symbol used to represent an unknown quantityconstanta term without a variable

A
Term variable goes to definition a letter or symbol used to represent an unknown quantity. Term coefficient goes to definition a term without a variable. Term constant goes to definition a numerical factor of a term that has a variable.
Option A
B
Term variable goes to definition a term without a variable. Term coefficient goes to definition a numerical factor of a term that has a variable. Term constant goes to definition a letter or symbol used to represent an unknown quantity.
Option B
C
Term variable goes to definition a letter or symbol used to represent an unknown quantity. Term coefficient goes to definition a numerical factor of a term that has a variable. Term constant goes to definition a term without a variable.
Option C
D
Term variable goes to definition a numerical factor of a term that has a variable. Term coefficient goes to definition a term without a variable. Term constant goes to definition a letter or symbol used to represent an unknown quantity.
Option D
6

What is the solution to –4(8 – 3x) ≥ 6x – 8?

A
x ≥ –
Option A
B
x ≤ –
Option B
C
x ≥ 4
D
x ≤ 4
8

The box below shows the first two of four steps for identifying equivalent expressions.• Simplify each expression. • Substitute a number for each variable. ••Which shows the last two steps in the directions?

A
• Compare the resulting expressions.• If they have identical terms, the expressions are equivalent.
B
• Compute the value of each expression. • Compare the values. If they are equal, the expressions are equivalent.
C
• Decide if there are like terms in each expression. • Compare the like terms to simplify each expression.
D
• Compare each expression, looking for like terms between them.• If each term matches one in the other expression, they are equivalent.
11

Solve the inequality.2(4+2x)≥5x+5

x
x≤−2
x
x≥−2
x
x≤3
x
x≥3

Did you find these answers helpful?

Solving One-Variable Inequalities — Unit test…