Unit Test — Unit test Answers
25 verified answers2 views
21
Free Preview
A student solves the following equation for all possible values of x:His solution is as follows: Step 1: 8(x – 4) = 2(x + 2)Step 2: 4(x – 4) = (x + 2)Step 3: 4x – 16 = x + 2Step 4: 3x = 18Step 5: x = 6He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0.Which best describes the reasonableness of the student’s solution?
A
His solution for x is correct and his explanation of the extraneous solution is reasonable.B
His solution for x is correct, but in order for 6 to be an extraneous solution, both denominators have to result in 0 when 6 is substituted for x.C
His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.D
His solution for x is incorrect. When solved correctly, there are no extraneous solutions.22
Free Preview
Which expression is equivalent to ?
A
StartFraction 1 Over 2 Superscript 15 Baseline EndFraction
B
StartFraction 1 Over 2 Superscript 8 Baseline EndFraction
C
28D
21523
What is the quotient of ?
A
StartFraction x Superscript 9 Baseline Over 32 EndFraction
B
4x9C
Negative StartFraction 12 Over x squared EndFraction
D
–2x924
What is the quotient?
A
Two-thirds
B
Three-halves
C
StartFraction (n + 3) squared Over 6 (n minus 3) squared EndFraction
D
StartFraction 6 (n minus 3) squared Over (n + 3) squared EndFraction
25
Anja simplified the expression to . What mistake did Anja make?
A
She divided the exponents instead of subtracting them.B
She divided the coefficients instead of subtracting them.C
She subtracted the coefficients instead of dividing them.D
She subtracted the exponents instead of dividing them.Did you find these answers helpful?
Verified answers available
TRY EDGENUITY HACKS
- Auto Complete Exams
- Auto Complete Assignments
- Skip Videos Instantly
50,000+ students using this