Which triangle has 0 reflectional symmetries?




Triangle ABC was transformed using the rule (x, y) → (–y, x). The vertices of the triangles are shown.A (–1, 1)B (1, 1)C (1, 4) A' (–1, –1)B' (–1, 1)C' (–4, 1)
On a coordinate plane, a trapezoid has points H prime (negative 3, negative 2), J prime (negative 2, negative 3), K prime (negative 3, negative 4), G prime (negative 5, negative 2).

On a coordinate plane, 2 parallelograms are shown. The first parallelogram has points A (negative 4, 4), B (negative 2, 4), C (negative 5, 1), D (negative 2, 1). The second parallelogram has points A prime (negative 2, 5), B prime (1, 5), C prime (negative 3, 2), D prime (0, 2).

Which shows the image of quadrilateral ABCD after the transformation R0, 90°?





Which transformations could have taken place? Select two options.
The image of trapezoid PQRS after a reflection across is trapezoid P'Q'R'S'.


Which statements are true about triangle ABC and its translated image, A'B'C'? Select two options.
The rule as a mapping for the translation of a rectangle is (x, y) → (x – 2, y + 7). Which describes this translation?
On a coordinate plane, a triangle has points A (negative 2, negative 2), B (1, negative 5), and C (negative 5, negative 5).

The image of ΔABC after a reflection across is ΔA'B'C'.



A rectangle on a coordinate plane is translated 5 units up and 3 units to the left. Which rule describes the translation?
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