Writing Linear Equations — Unit test Answers

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Question illustration
A
Option
Option A
B
Option
Option B
C
(8, –4)
D
(10, –7)
6

Consider the diagram.

Question illustration
A
intersecting.
B
parallel.
C
perpendicular.
D
skew.
7

Which diagram shows lines that must be parallel lines cut by a transversal?

A
2 horizontal lines are intersected by a third line. At the intersection of the first line with the third line, the bottom left angle is 115 degrees. At the intersection of the second line with the third line, the uppercase left angle is 65 degrees.
Option A
B
2 horizontal lines are intersected by a third line. At the intersection of the first line with the third line, the bottom left angle is 115 degrees and the bottom right angle is 65 degrees.
Option B
C
2 horizontal lines are intersected by a third line. At the intersection of the first line with the third line, the top right angle is 115 degrees. At the intersection of the second line with the third line, the uppercase left angle is 115 degrees.
Option C
D
2 horizontal lines are intersected by a third line. At the intersection of the first line with the third line, the uppercase left angle is 65 degrees and the bottom right angle is 65 degrees.
Option D
10

On a coordinate plane, 2 lines are shown. Line C D has points (negative 2, 4) and (0, negative 4). Line F G has points (negative 4, 0) and (4, 2).

Question illustration
A
They are perpendicular because their slopes are equal.
B
They are perpendicular because their slopes are negative reciprocals.
C
They are not perpendicular because their slopes are equal.
D
They are not perpendicular because their slopes are negative reciprocals.
12

Consider the diagram.

Question illustration
A
corresponding angles theorem
B
alternate interior angles theorem
C
vertical angles theorem
D
alternate exterior angles theorem
15

A line contains points M(1, 3) and N(5, 0). What is the slope of MN?

A
negative StartFraction 4 Over 3 EndFraction
Option A
B
negative StartFraction 3 Over 4 EndFraction
Option B
C
StartFraction 3 Over 4 EndFraction
Option C
D
StartFraction 4 Over 3 EndFraction
Option D
16

Segment CD is shown on the graph.

Question illustration
A
y = (3 – 1) + 1
Option A
B
y = (3 + 4) – 4
Option B
C
y = (3 – 1) + 1
Option C
D
y = (3 + 4) – 4
Option D

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