In a dihybrid cross for round and yellow seeds (RrYy x RrYy), what is the probability of having green and wrinkled seeds? Key: R is equal to round r is equal to wrinkled Y is equal to yellow y is equal to green

In the RrYy × RrYy cross, each parent has a 1/4 chance of passing on r and a 1/4 chance of passing on y. Green and wrinkled seeds must be rryy, so multiply the independent probabilities: 1/4 × 1/4 = 1/16. The correct choice is A, 1 : 16.

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