Question 48 • Chemistry
Add the two equations so the P₄ and Cl₂ terms cancel. This gives 4 PCl₅(g) → 4 PCl₃(g) + 4 Cl₂(g), with ΔH = 3,438 kJ − 2,439 kJ = 999 kJ. Divide the equation and enthalpy by 4 to get ΔH = 999 ÷ 4 = 249.75 kJ, or about 250 kJ. The correct choice is 250 kJ.
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