The chemical equation shows the combustion of methane open paren CH sub 4 close paren CH sub 4 plus 2 cap o sub 2 rightarrow CO sub 2 plus 2 cap h sub 2 cap o The molar mass of oxygen gas open paren cap o sub 2 close paren is 32 point 0 0 g over mol The molar mass of carbon dioxide open paren CO sub 2 close paren is 44 point 0 1 g over mol What mass of CO sub 2 , in grams, will form when 8 point 9 4 g cap o sub 2 completely react?
Convert oxygen to moles: 8.94 g ÷ 32.00 g/mol = 0.279 mol O₂. The balanced equation shows that 2 mol O₂ produce 1 mol CO₂, so this forms 0.1397 mol CO₂. Multiplying by its molar mass gives 0.1397 mol × 44.01 g/mol = 6.15 g CO₂, which is choice D.
AI-written and checked against the verified answer.